If $Δ = ∣ ∣ ∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣ ∣ ∣$ $A_{i}, B_{i}, C_{i}$ are respectively are cofator of $a_{i}, b_{i}, c_{i}$ -- for all i = 1, 2, 3, then

$∣ ∣ ∣ ∣ \begin{matrix} A_{1} & B_{1} & C_{1} A_{2} & B_{2} & C_{2} A_{3} & B_{3} & C_{3} \end{matrix} ∣ ∣ ∣ ∣$

∆

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$\Delta^2$

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2∆

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Solution

The correct option is C
$\Delta^2$

Given determinate =|adj A| = $| A^{2} |$ = $Δ^{2}$

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