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Question

If Δ=∣ ∣ ∣sinαcosαsin(α+δ)sinβcosβsin(β+δ)sinγcosγsin(γ+δ)∣ ∣ ∣ then Δ is independent of

A
α
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B
β
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C
γ
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D
δ
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Solution

The correct options are
A α
B β
C γ
D δ
Δ=∣ ∣ ∣sinαcosαsin(α+δ)sinβcosβsin(β+δ)sinγcosγsin(γ+δ)∣ ∣ ∣
Applying C3C3cosδC1sinδC2
Δ=∣ ∣sinαcosα0sinβcosβ0sinγcosγ0∣ ∣=0

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