If ΔE is the heat of reaction for C2H5OH(l)+3O2(g)⟶2CO2(g)+3H2O(l) at constant volume, the ΔH (heat of reaction at constant pressure), at constant temperature is:
A
ΔH=ΔE+RT
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B
ΔH=ΔE−RT
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C
ΔH=ΔE−2RT
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D
ΔH=ΔE+2RT
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Solution
The correct option is CΔH=ΔE−RT We know that, ΔH=ΔE+ΔnRT where, Δn= number of moles of gaseous products - number of moles of gaseous reactants =2−3=−1 So, ΔH=ΔE−RT