If - G - -177 K cal for 1 2Fes - 32 O2g - Fe2O3sand - G - -19 K cal for2 4Fe2O3s - Fes - 3Fe3O4sWhat is the Gibbs free energy of formation of Fe3O4-

The correct option is B 242.3 kcalmol 2Fe(s)+32O_2(g) ⟶ Fe_2O_3(s) , #160; #160; #160; Δ G= 177KCal ⟶ (1) 4Fe_2O_3(s)+Fe(s) ⟶ 3Fe ...

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Equipartition Theorem

If Δ G = -1...

Question

If $Δ G = - 177 K c a l$ for
(1) $2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)$
and $Δ G = - 19 K$ cal for
(2) $4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)$
What is the Gibbs free energy of formation of $F e_{3} O_{4}$ ?

+ 229.6 \frac{k c a l}{m o l}

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- 242.3 \frac{k c a l}{m o l}

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- 727 \frac{k c a l}{m o l}

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- 229.6 \frac{k c a l}{m o l}

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Similar questions

Δ G = - 177 k cal

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 k cal

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4} (s)

$Δ G = - 177 K c a l$ for $2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)$ and

What is the Gibbs free energy of formation of $F e_{3} O_{4}$ ?;

Δ G = - 177

(1)

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19

(2)

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4}

Δ G = - 177 k cal

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 k cal

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4} (s)

Δ G = - 177

2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s)

Δ G = - 19 K c a l

4 F e_{2} O_{3} (s) + F e (s) \to 3 F e_{3} O_{4} (s)

F e_{3} O_{4} (s)

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