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Question

If ΔG=177Kcal for 2Fe(s)+32O2(g)Fe2O3(s) and ΔG=19Kcal for 4Fe2O3(s)+Fe(s)3Fe3O4(s). What is the Gibbs free energy of formation of Fe3O4(s)?

A
+229.6 kcal/mol
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B
242.3 kcal/mol
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C
727 kcal/mol
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D
229.6 kcal/mol
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Solution

The correct option is B 242.3 kcal/mol
Given, 2Fe+32O2Fe2O3....(i) G=177 KCal
4Fe2O3+Fe3Fe3O4....(ii) G=19 KCal
Divide by (iii) in reaction (ii)
43Fe2O3+13FeFe3O4....(iii) G=193 KCal
Similarly, multiply by 43 in reaction (i)
83Fe+43×32O243Fe2O3....(iv) G=177×43 Kcal
Now from (iii) and (iv)
83Fe+2O243Fe2O3....(iv) 177×43 Kcal
43Fe2O3+13Fe2Fe3O4....(iii) 193 Kcal
_____________________________________________
Now adding (iv) and (iii)
3Fe(s)+2O2(g)Fe3O4 G=(177×43193) Kcal
G=242.3 Kcal/mol


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