If - G- - 0 for a reaction- then-

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Standard XII

Chemistry

Characteristics of Chemical Equilibrium

If Δ G∘ > 0...

Question

If $Δ G^{\circ} > 0$ for a reaction, then:

K_{p} > 1

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K_{p} < 1

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The products predominate in the equilibrium mixture

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None of the above

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Solution

The correct option is B $K_{p} < 1$
When $Δ G^{\circ} > 0$ , the reaction is non-spontaneous. Thus, the equilibrium mixture contains more reactants than products. Hence, the value of equilibrium constant is less than 1.
Hence, $K_{p} < 1$ .

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Similar questions

The reaction N $_{2}$ O $_{4}$ (g) $⇌$ 2NO $_{2}$ (g) is
carried out at 298 K and 20 bar. Five moles of each of N $_{2}$ O $_{4}$ and
NO $_{2}$ , are taken initially. Given: $Δ$ $_{f}$ G $^{\circ}$
(N $_{2}$ O $_{4}$ ) = 100 kJ mol $^{- 1}$ and $Δ$ $_{f}$ G $^{\circ}$
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Q. If

log \frac{k_{c}}{k_{p}} - log \frac{1}{R T} = 0

, then above is true for the following equilibrium reaction:

Q. For a gaseous reaction,

2 B_{(g)} ⇌ A_{(g)}

, the equilibrium constant

K_{p}

is less than

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If the above statement is true enter 1, if false enter 0.

For thedecomposition reaction 4 $H N O_{3}$ (g) $⇋$ 4 $N O_{2}$ (g) + 2 $H_{2}$ O (g) + $O_{2}$ (g) if we start with only the reactant $H N O_{3}$ and p = equilibrium pressure, the equilibrium constant $K_{p}$ is:

Q. The equilibrium constant

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If ΔG∘>0 for a reaction, then:

The correct option is B Kp<1When ΔG∘>0, the reaction is non-spontaneous. Thus, the equilibrium mixture contains more reactants than products. Hence, the value of equilibrium constant is less than 1.Hence, Kp<1.

If $Δ G^{\circ} > 0$ for a reaction, then:

The correct option is B $K_{p} < 1$
When $Δ G^{\circ} > 0$ , the reaction is non-spontaneous. Thus, the equilibrium mixture contains more reactants than products. Hence, the value of equilibrium constant is less than 1.
Hence, $K_{p} < 1$ .