If Δ G =Δ H -...

Question

If $Δ G = Δ H - T Δ S$ and $Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{p}$ then variation of EMF of a cell with temperature T is given by

\frac{Δ G}{n F}

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\frac{Δ S}{n F}

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\frac{Δ H}{n F}

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\frac{- Δ S}{n F}

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Solution

The correct option is B $\frac{Δ S}{n F}$
Comparing the given two expressions

$[\frac{d (Δ G)}{d T}] = - Δ S$ (or) $\frac{d (- n F E)}{d T} = - Δ S$

(or) $n F (\frac{d E}{d T}) = Δ S$ (or) $\frac{d E}{d T} = \frac{Δ S}{n F}$

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Similar questions

Δ G = Δ H - T Δ S

Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{P}

$Δ G = Δ H - T Δ S$ and $Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{p}$ , then $(\frac{d E_{c e l l}}{d T})$ is:

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

Δ S

(E_{c e l l})

Δ G = n F E_{c e l l}

Δ G

d (Δ G) = (Δ V) d p - (Δ S) d T

d (Δ G) = - (Δ S) d T

Δ G = Δ H - T Δ S

∴ Δ G = Δ H + T {(\frac{d (Δ G)}{Δ T})}_{P}

{(\frac{d E_{c e l l}}{d T})}_{p}

{(\frac{d E}{d T})}_{p}

Δ H

Δ S

Δ G

Δ G = Δ H - T Δ S