If ΔHvaporisation of substance X(1) (molar mass: 30 g/mol) is 300 J/g at its boiling point 300 K, then molar entropy change for reversible condensation process is
− 30 J/mol. K
ΔHvaporisation = 300 × 30 J/mol
ΔScondensation = −ΔHvaporisationTboiling point
=−300 × 30300J/mol.K
= −30 J/molK