If - U of combustion of CH4g- CH4g - 2O2g - CO2g - 2H2Olat certain temperature is -393 kJ mol-1- The value of - H is-

The reaction is nbsp; CH_4(g) nbsp; + 2O_2(g) → CO_2(g) + 2H_2O(l) Δ n_g =( n_p n_r)_g=1 3= 2 and nbsp; Δ H = Δ U+Δ n_gRT nbsp; As, Δ n_g = 2 so, n ...

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Standard XI

Chemistry

Enthalpy

If Δ U of com...

Question

If $Δ U$ of combustion of $C H_{4} (g)$ ,
$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$
at certain temperature is $- 393 k J m o l^{- 1}$ . The value of $Δ H$ is:

zero

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< Δ U

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> Δ U

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equal to

Δ U

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Solution

The correct option is B $< Δ U$
The reaction is
$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$
$Δ n_{g} = (n_{p} - n_{r})_{g} = 1 - 3 = - 2$
and
$Δ H = Δ U + Δ n_{g} R T$
As, $Δ n_{g} = - 2$
so,
$\Rightarrow Δ H < Δ U$

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Similar questions

Q. If

Δ U

of combustion of

C H_{4} (g)

C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)

at certain temperature is

- 393 k J m o l^{- 1}

. The value of

Δ H

is:

Δ U^{0}

of combustion of

C H_{4_{(} g)}

at certain temperature is -393 kJ

m o l^{- 1}

. The value of

Δ H^{0}

is:

Complete and balance the following reaction:

${CH}_{4} (g) + O_{2} (g) \to$

C H_{4} (g) + 2 O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l)

;

Δ H = - 890 k J

. What is the calorific or fuel value of

1 k g

C H_{4}

Q. At

298 K

, the enthalpy of combustion of

C H_{4}

corresponds to the reaction

C H_{4} (g) + 2 O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (g)

.If true enter 1 else o

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Enthalpy

Standard XI Chemistry

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If ΔU of combustion of CH4(g), CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) at certain temperature is −393 kJmol−1. The value of ΔH is:

The correct option is B <ΔU The reaction is CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) Δng=(np−nr)g=1−3=−2 and ΔH=ΔU+ΔngRT As, Δng=−2 so, ⇒ΔH<ΔU

If $Δ U$ of combustion of $C H_{4} (g)$ ,
$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$
at certain temperature is $- 393 k J m o l^{- 1}$ . The value of $Δ H$ is:

The correct option is B $< Δ U$
The reaction is
$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$
$Δ n_{g} = (n_{p} - n_{r})_{g} = 1 - 3 = - 2$
and
$Δ H = Δ U + Δ n_{g} R T$
As, $Δ n_{g} = - 2$
so,
$\Rightarrow Δ H < Δ U$