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Question

If [.]denotes G.I F, 2π0[|sin x||cos x|]dx=


A

2π

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B

4π

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C

π

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D

0

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Solution

The correct option is C

π


|sinx||cosx|[1,1]2π0[|sin x||cos x|]dx=2π0[|sin x||cos x|]dx=2(π40[|sin x||cos x|]dx+3π4π4[|sin x||cos x|]dx+π3π4[|sin x||cos x|]dx)=2(π40(1)dx+3π4π40dx+π3π4(1)dx)=π


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