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Question

If [ ] denotes the greatest integer function then f(x)=[x]+[x+12]

A
is continuous at x=12
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B
is discontinuous at x=12
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C
limx(1/2)+f(x)=2
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D
limx(1/2)f(x)=1
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Solution

The correct option is C is discontinuous at x=12

f(x)=[x]+[x+12]f(x)x1/2=limh0[12h]+[12h+12]f(x)x1/2=limh00+[1h]=limh00+1+[h]=11=0f(x)x1+/2=limh0[12+h]+[12+h+12]f(x)x1+/2=0+1=1f(x)x1/2f(x)x1+/2

So, function is discontinuous at x=12.


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