If density of $2$ molal sucrose solution is $1.4 g m / m L$ at $25$ find osmotic pressure.

4.06

atm

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2

atm

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40.6

atm

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3.4

atm

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Solution

The correct option is B $40.6$ atm
Given
Density $= 1.4 g / m l$
Molecular weight $= 342$
and m $= 2$
Now,
Molarity $M = \frac{1000 \times m \times d e n s i t y}{1000 \times m \times m o l e c u l a r w e i g h t}$
$M = \frac{1000 \times 2 \times 1.4}{1000 \times 2 \times 342}$
$M = 1.662$
Now,
Osmotic pressure $= i M R T$
$= 1 \times 1.662 \times 0.082 \times 298$
$= 40.6 a t m$

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If density of 2 molal sucrose solution is 1.4 gm/mL at 25 find osmotic pressure.

The correct option is B 40.6 atmGivenDensity=1.4 g/ml Molecular weight=342 and m=2Now,Molarity M=1000×m×density1000×m×molecularweightM=1000×2×1.41000×2×342M=1.662Now,Osmotic pressure=iMRT =1×1.662×0.082×298 =40.6 atm

If density of $2$ molal sucrose solution is $1.4 g m / m L$ at $25$ find osmotic pressure.