If density of the earth is doubled keeping its radius constant, then acceleration due to gravity (present value $9.8 m / s^{2}$ ) will be:

2.45 m / s^{2}

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4.9 m / s^{2}

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9.8 m / s^{2}

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19.6 m / s^{2}

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Solution

The correct option is B $19.6 m / s^{2}$
The value of $g = \frac{G M}{R^{2}}$ .
If the density of earth is doubled keeping volume same, then the mass of the earth is also doubled. So, $M$ becomes $2 M$ .
So, the value of $g$ will be doubled.

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If density of the earth is doubled keeping its radius constant, then acceleration due to gravity (present value 9.8m/s2) will be:

The correct option is B 19.6 m/s2The value of g=GMR2.If the density of earth is doubled keeping volume same, then the mass of the earth is also doubled. So, M becomes 2M.So, the value of g will be doubled.

If density of the earth is doubled keeping its radius constant, then acceleration due to gravity (present value $9.8 m / s^{2}$ ) will be:

The correct option is B $19.6 m / s^{2}$
The value of $g = \frac{G M}{R^{2}}$ .
If the density of earth is doubled keeping volume same, then the mass of the earth is also doubled. So, $M$ becomes $2 M$ .
So, the value of $g$ will be doubled.