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Question

If 1(a+1),13a,1(4a+2) are in harmonic progression, then the value of a will be

A
15
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B
12
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C
13
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D
14
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Solution

The correct option is C 13
The reciprocal of A.P. is H.P.
A..P is in the form of a+1,3a,4a+2,...
Common difference, d= second term first term
3a(a+1)=4a+23a
2a1=a+2
a=3
Therefore, the value of a in H..P is 13.

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