Question

If $\frac{1}{\sqrt{\alpha }}$ and $\frac{1}{\sqrt{\beta }}$ are the roots of the equation, $a{x}^2+bx+1=0$ $(a\ne 0,a,b\in R)$, then the equation, $x(x+b^3)+(a^3-3abx)=0$ has roots

• A. ${\alpha }^{3/2}$ and ${\beta }^{3/2}$
• B. $\alpha {\beta }^{1/2}$ and ${\alpha }^{1/2}\beta$
• C. $\sqrt{\alpha \beta }$ and $\alpha \beta$
• D. ${\alpha }^{-3/2}$ and ${\beta }^{-3/2}$

Answer 1

The correct option is A ${\alpha }^{3/2}$ and ${\beta }^{3/2}$