Question

If $\frac{1}{x-y}=\frac{1}{2}$ and $\frac{1}{x+y}=\frac{1}{14}$ then find the value of x.

Answer 1

$\begin{array}{c}\frac{1}{x-y}=\frac{1}{2}and\frac{1}{x+y}=\frac{1}{14}\\ x-y=\mathrm{2...}\left(i\right)andx+y=\mathrm{13....}\left(ii\right)\\ byaddingeq\left(i\right)\&\left(ii\right)\\ \underset{–}{\begin{array}{c}x-y=2\\ x+y=14\end{array}}|\\ 2x=16\\ x=8\end{array}$