Question

If $\frac{17-3x}{5}-\frac{4x+2}{3}=5-6x+\frac{7x+14}{3}$, find the value of $x$.

• A. $2$
• B. $4$
• C. $-4$
• D. $-2$

Answer 1

The correct option is B $4$

$\frac{17-3x}{5}-\frac{4x+2}{3}=5-6x+\frac{7x+14}{3}$

$⟹\frac{3(17-3x)-5(4x+2)}{15}=\frac{3(5-6x)+7x+14}{3}$

$⟹\frac{51-9x-20x-10}{15}=\frac{15-18x+7x+14}{3}$

$⟹\frac{41-29x}{15}=\frac{29-11x}{3}$

$⟹41-29x=\frac{15}{3}(29-11x)$

$⟹41-29x=145-55x$

$⟹-29x+55x=145-41$

$⟹26x=104$

$⟹x=\frac{104}{26}=4$