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Question

If $$\dfrac { 17-3x }{ 5 } -\dfrac { 4x+2 }{ 3 } =5-6x+\dfrac { 7x+14 }{ 3 } $$, find the value of $$x$$.


A
2
loader
B
4
loader
C
4
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D
2
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Solution

The correct option is B $$4$$
$$\dfrac{17-3x}{5}-\dfrac{4x+2}{3}=5-6x+\dfrac{7x+14}{3}$$

$$\implies \dfrac{3(17-3x)-5(4x+2)}{15}=\dfrac{3(5-6x)+7x+14}{3}$$

$$\implies \dfrac{51-9x-20x-10}{15}=\dfrac{15-18x+7x+14}{3}$$

$$\implies \dfrac{41-29x}{15}=\dfrac{29-11x}{3}$$

$$\implies 41-29x=\dfrac{15}{3}(29-11x)$$

$$\implies 41-29x=145-55x$$
$$\implies -29x+55x=145-41$$
$$\implies 26x=104$$

$$\implies x=\dfrac{104}{26}=4$$

Mathematics

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