Question

If $\frac{2}{3},k,\frac{5}{8}$ are in AP, find the value of k.

• A. $\frac{48}{31}$
• B. $\frac{31}{48}$
• C. $\frac{17}{29}$
• D. $\frac{29}{17}$

Answer 1

Answer: (B)

$\frac{31}{48}$

$\frac{2}{3},k,\frac{5}{8}$ are in AP.

Thus, $k-\frac{2}{3}=\frac{5}{8}-k$

$2k=\frac{2}{3}+\frac{5}{8}$

$2k=\frac{31}{24}$

$k=\frac{31}{48}$.