If 23x - 12 - 23- then the value of x - 4 is

The correct option is B 1 Given 2 3x+12 = 2 3 ⇒ 3(2)=2(3x+12) ⇒ 6=6x+24 ⇒ 6x= 18 ⇒ x= 3 Therefore x+4= 3+4=1 ...

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Reducing Equations to Simpler Form

If 23x + 12...

Question

If $\frac{2}{3 x + 12} = \frac{2}{3}$ , then the value of $x + 4$ is

\frac{1}{2}

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1

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\frac{3}{2}

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2

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∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & x + 1 & x - 2 2 x^{2} + 3 x - 1 & 3 x & 3 x - 3 x^{2} + 2 x + 3 & 2 x - 1 & 2 x - 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = A x - 12

A

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & x + 1 & x - 2 {2 x}^{2} + 3 x - 1 & 3 x & 3 x - 3 x^{2} + 2 x + 3 & 2 x - 1 & 2 x - 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x - 12,

a^{2}

\frac{\frac{2}{3} + \frac{1}{x - 4}}{1 - \frac{2}{3 x - 12}}

x = 1 + 2^{1 / 3} + 2^{2 / 3}

x^{3} - 3 x^{2} - 3 x - 1

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & 3 x - 1 & - x + 3 2 x + 1 & 2 + x^{2} & x^{3} - 3 x - 3 & x^{2} + 4 & 3 x \end{matrix} ∣ ∣ ∣ ∣ ∣ = a_{0} + a_{1} x + a_{2} x^{2} + . . . + a_{7} x^{7}

a_{0}

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