If 29- - 23-7- - 15-5- - 2ab- where a- b- N then the ordered pair a- b is

The correct option is C (9, 10) 29! + 23!7! + 15!5! =19! [2 + 2.8.93! + 6.7.8.95! ] = 19! [2 + 8× 3 + 6.7.8.95.4.3.2 ] = 19! [2 + 24 + 1265 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Mathematics

Intersection

If 29! + 23...

Question

If $\frac{2}{9!} + \frac{2}{3! 7!} + \frac{1}{5! 5!} = \frac{2^{a}}{b!}$ where $a, b ϵ N$ then the ordered pair $(a, b)$ is

(10, 9)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(10, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(9, 10)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(5, 10)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(9, 10)$
$\frac{2}{9!} + \frac{2}{3! 7!} + \frac{1}{5! 5!}$
$= \frac{1}{9!} [2 + \frac{2.8.9}{3!} + \frac{6.7.8.9}{5!}] = \frac{1}{9!} [2 + 8 \times 3 + \frac{6.7.8.9}{5.4.3.2}]$
$= \frac{1}{9!} [2 + 24 + \frac{126}{5}] = \frac{1}{9!} [26 + \frac{126}{5}] = \frac{256 \times 2}{9! .5 \times 2} = \frac{512}{10!} \Rightarrow \frac{2^{9}}{10!}$
Hence $a = 9, b = 10$

Suggest Corrections

Similar questions

Q. If

x = 2 + 5 i (

where

1 i = \sqrt{- 1})

and

2 (\frac{1}{1! 9!} + \frac{1}{3! 7!}) + \frac{1}{5! 5!} = \frac{2^{a}}{b!}

then

x^{3} - 5 x^{2} + 33 x - 10 =

If A = $⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 4 & 5 & 6 7 & 8 & 9 \end{matrix} ⎤ ⎥ ⎦$ and B = $⎡ ⎢ ⎣ \begin{matrix} 4 & 5 & 6 7 & 8 & 9 1 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦$ then the order of A+B will be nxn where n= -----

___

Q. If A and B are two matrices of same order

3 \times 3

where A=

⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 3 & 4 5 & 6 & 7 \end{matrix} ⎤ ⎥ ⎦

and B=

⎡ ⎢ ⎣ \begin{matrix} 3 & 2 & 5 2 & 3 & 8 7 & 2 & 9 \end{matrix} ⎤ ⎥ ⎦

AB=?

Q. If

A = (1, 3, 5, 7, 9)

and

B = (2, 3, 5, 7)

, what is

A \cup B

Q. Let

U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

. If

A = {1, 2, 5}

and

B = {6, 7},

then

A \cap B^{'}

Join BYJU'S Learning Program

If 29!+23!7!+15!5!=2ab! where a,bϵN then the ordered pair (a,b) is

The correct option is C (9,10)29!+23!7!+15!5!=19![2+2.8.93!+6.7.8.95!]=19![2+8×3+6.7.8.95.4.3.2]=19![2+24+1265]=19![26+1265]=256×29!.5×2=51210!⇒2910!Hence a=9,b=10

If $\frac{2}{9!} + \frac{2}{3! 7!} + \frac{1}{5! 5!} = \frac{2^{a}}{b!}$ where $a, b ϵ N$ then the ordered pair $(a, b)$ is