If 2x x2 - x - 12- then the value of x - 1 is

The correct option is D 14 Given, 2x ( x ^ 2 +x) = 12 ⇒2x× x (x+1) = 12 ⇒ 2 × (x+1) = 12 #160; ⇒ x+1 = 14 ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Binomial Coefficients

If 2x x2 + ...

Question

If $\frac{2}{x} (x^{2} + x) = \frac{1}{2}$ , then the value of $x + 1$ is

\frac{1}{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\sqrt{1 + \frac{1}{1^{2}} + \frac{1}{2^{2}}} + \sqrt{1 + \frac{1}{2^{2}} + \frac{1}{3^{2}}} + \sqrt{1 + \frac{1}{3^{2}} + \frac{1}{4^{2}}} + . . . . . + \sqrt{1 + \frac{1}{(1999)^{2}} + \frac{1}{(2000)^{2}}} = x - \frac{1}{x}

x

3 (x - 1) = 6 + 2 (x - 3)

\frac{(x + 1)^{2}}{(x - 2)} + \frac{4}{(x + 1)}

3 {sin}^{- 1} (\frac{2 x}{1 + x^{2}}) - 4 {cos}^{- 1} (\frac{1 - x^{2}}{1 + x^{2}}) + 2 {tan}^{- 1} (\frac{2 x}{1 - x^{2}}) = \frac{π}{3}

x

(x + \frac{1}{x}) = 3

x - \frac{1}{x}

x^{2} - \frac{1}{x^{2}}

x^{4} - \frac{1}{x^{4}}

x = 7 + 4 \sqrt{3}

x^{\frac{1}{2}} + x^{- \frac{1}{2}}

Join BYJU'S Learning Program