Question

If $\frac{2}{x}(x^2+x)=\frac{1}{2}$, then the value of $x+1$ is

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $1$
• D. $\frac{3}{2}$
• E. $2$

Answer 1

Answer: (A)

$\frac{1}{4}$

Given, $\frac{2}{x}(x^2+x)=\frac{1}{2}$
$\Rightarrow \frac{2}{x}\times x(x+1)=\frac{1}{2}$
$\Rightarrow 2\times (x+1)=\frac{1}{2}$

$\Rightarrow x+1=\frac{1}{4}$