Question

if $\frac{(23{)}^9-(23{)}^8}{22}=(23{)}^x$ then $x$ equals :

• A. $7$
• B. $8$
• C. $9$
• D. $1$

Answer 1

The correct option is B $8$

$LHS=\frac{(23{)}^9-(23{)}^8}{22}$
$=\frac{{23}^8(23-1)}{22}$
$=\frac{{23}^8\times 22}{22}$
$={23}^8$

$RHS={23}^x$

On comparing $LHS$ and $RHS$ we get,
$x=8$