Question

If $\frac{241}{4000}=\frac{241}{2^m{5}^n}$, find $m$ and $n$ values?

Answer 1

It is given that,

$\frac{241}{4000}=\frac{241}{2^m{5}^n}$

Since, $4000=2^5\times 5^3$, then,

$\frac{241}{2^5{5}^3}=\frac{241}{2^m{5}^n}$

By comparing both sides,

$m=5$ and $n=3$.