If 2x2-3x-4x-1x2-2-Ax-1-Bx-Cx2-2 Then the value of B is equal to

The correct option is C 1 LHS=2x^2+3x+4(x 1)(x^2+2); #160;RHS=A(x^2+2)+(Bx+C)(x 1)(x 1)(x^2+2) LHS=RHS 2x^2+3x+4=A(x^2+2)+(Bx+C)(x 1) E ...

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Integration by Partial Fractions

If 2x2+3x+4...

Question

If $\frac{2 x^{2} + 3 x + 4}{(x - 1) (x^{2} + 2)} = \frac{A}{x - 1} + \frac{B x + C}{x^{2} + 2}$ Then the value of $B$ is equal to

3

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\frac{3 x + 2}{(x + 1) (2 x^{2} + 3)} = \frac{A}{(x + 1)} + \frac{B x + C}{(2 x^{2} + 3)}

A + C - B =

\int \frac{2 x^{2} + 3}{(x^{2} - 1) (x^{2} + 4)} d x = A l o g (\frac{x + 1}{x - 1}) + B t a n^{- 1} (\frac{x}{2}) + C

\int \frac{2 x^{2} + 3}{(x^{2} - 1) (x^{2} + 4)} d x = a log (\frac{x - 1}{x + 1}) + b {tan}^{- 1} (\frac{x}{2}) + c

b

f (x) = x^{2} + b x + c

\frac{1}{4}

g (x) = - x^{2} + b x + 2

x = \frac{3}{2}

∣ ∣ ∣ ∣ \begin{matrix} x^{2} + 3 x & x + 1 & x - 2 x - 1 & 1 - 2 x & x + 4 x + 3 & x - 4 & 3 x \end{matrix} ∣ ∣ ∣ ∣ = A x^{4} + B x^{3} + C x^{2} + D x + ϱ

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