If 3 - 13 - 333 - 12 - 32 - x - 40- then x - -

(3 1)^3+(3)^3(3 1)^2+(3)^2 x=40 (2)^3+27(2)^2+9 x=40 8+274+9 x=40 3513 x=401 By Cross multiplying , we get 35=40(13 x) 35=520 40x ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of Coefficients of All Terms

If 3 - 13 +...

Question

If $\frac{(3 - 1)^{3} + (3)^{3}}{(3 - 1)^{2} + 3^{2} - x} = 40$ , then $x = ?$

Open in App

Solution

Suggest Corrections

Similar questions

3 (\frac{3 x - 1}{2 x + 3}) - 2 (\frac{2 x + 3}{3 x - 1}) = 5; x \neq \frac{1}{3}, - \frac{3}{2}

3 (\frac{3 x - 1}{2 x + 3}) - 2 (\frac{2 x + 3}{3 x - 1}) = 5, x \neq \frac{1}{3}, - \frac{3}{2}

x + \frac{1}{x} + 2 = 0,

x^{33} + x^{32} + x^{13} + x^{12} + x + 1

\frac{1}{(x - 2) (x - 3)^{3}} = \frac{A}{x - 2} + \frac{B}{x - 3} + \frac{C}{(x - 3)^{2}} + \frac{D}{(x - 3)^{3}}

B =

1^{3} + 1^{2} + 1 + 2^{3} + 2^{2} + 2 + 3^{3} + 3^{2} + 3 + . . . 3 n

=

Join BYJU'S Learning Program