Question

If $\frac{3}{4}$ quantity of a radioactive nuclide disintegrates in two hours, its half-life (an hour) will be:

Answer 1

$t=\frac{2.305\times t1/2}{0.693}\times log\frac{1}{\frac{1}{4}}$

$2=\frac{2.303\times t1/2}{0.693}\times log4$

$t1/2=0.99\approx 1hr$