Question

If $\frac{3}{7}+x+\left(\frac{-8}{21}\right)+\frac{5}{22}=\frac{-125}{462}$ then $x$ is

• A. $\frac{-4}{11}$
• B. $\frac{-5}{11}$
• C. $\frac{-6}{11}$
• D. $\frac{-7}{11}$

Answer 1

The correct option is C $\frac{-6}{11}$

If $\frac{3}{7}+x+\left(\frac{-8}{21}\right)+\frac{5}{22}=\frac{-125}{462}$

$\to \frac{3}{7}+x\frac{-8}{21}+\frac{5}{22}=\frac{-125}{462}$

$\therefore \frac{3\times 3\times 22+462x-8\times 22+5\times 21}{462}=\frac{-125}{462}$

$\therefore 198+462x-176+105=-125$

$\therefore 462x=-125+176-105-198$

$=-428+176$

$\therefore 462x=-252$

$\therefore x=\frac{-252}{462}=-\frac{2\times 2\times 7\times 3\times 3}{21\times 22}$

$\therefore x=\frac{-6}{11}$