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Question

If 3713=2+1x+1y+1z, where x,y,z are positive integer, then x+y+z is equal to

A
14
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B
10
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C
12
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D
8
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Solution

The correct option is C 8
3713=2+1x+1y+1z

37132=1x+1y+1z

1113=1x+1y+1z

x+1y+1z=1311

x+1y+1z=1+211

x=1and1y+1z=211

Now,
1y+1z=211

y+1z=112=5+12

y=5and1z=12

y=5andz=2

So, x+y+z=1+5+2=8

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