If 3n2 - 4n - 33- then n -

The correct option is A 6 Given, #160; 3n 2 = 4n+3 3 #160; ⇒ 3(3n)=2(4n+3) #160; #160; #8230;[Cross multiplying the denominators] ...

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Solving Equations with Variables on Both Sides

If 3n2 = 4n...

Question

If $\frac{3 n}{2} = \frac{4 n + 3}{3}$ , then $n =$ ?

6

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Δ_{r} = ∣ ∣ ∣ ∣ ∣ \begin{matrix} r & n & 6 r^{2} & {2 n}^{2} & 4 n - 2 r^{3} & {3 n}^{3} & 3 n^{2} - 3 n \end{matrix} ∣ ∣ ∣ ∣ ∣

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(\begin{matrix} \frac{- 15}{7} \div \frac{9}{11} \end{matrix}) \div \frac{3}{13} = \frac{- 15}{7} \div (\begin{matrix} \frac{9}{11} \div \frac{3}{13} \end{matrix})

1

0

2^{n} - (n - 1) 2^{n - 2} + \frac{(n - 2) (n - 3)}{⌊ 2} - \frac{(n - 3) (n - 4) (n - 5)}{⌊ 3} 2^{n - 6} + . . . . .;

3

1 - (n - 1) + \frac{(n - 2) (n - 2)}{⌊ 2} - \frac{(n - 3) (n - 4) (n - 5)}{⌊ 3} + . . . . = (- 1)^{n}

D_{r} =

∣ ∣ ∣ ∣ ∣ \begin{matrix} r - 1 & n & 6 {(r - 1)}^{2} & 2 n^{2} & 4 n - 2 {(r - 1)}^{3} & 3 n^{3} & 3 n^{2} - 3 n \end{matrix} ∣ ∣ ∣ ∣ ∣

n \sum r = 1 D_{r} =

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