If 5x-3y-10 and 3x-5y-6- then 1x-1y-

The correct option is A 2 5/x 3/y=10 ——– (1) 3/x 5/y=6 ——– (2)Multiply equation (1) by (3) amp; (4) by (5) then subtract 9/y=30 2 ...

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Standard VI

Mathematics

Equivalent Ratios

If 5x-3y=10...

Question

If $\frac{5}{x} - \frac{3}{y} = 10$ and $\frac{3}{x} - \frac{5}{y} = 6$ , then $\frac{1}{x} + \frac{1}{y} = . . .$

\frac{1}{2}

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- \frac{1}{2}

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2

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- 2

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Solution

The correct option is A $2$
$\frac{5}{x} - \frac{3}{y} = 10$ -------- (1)
$\frac{3}{x} - \frac{5}{y} = 6$ -------- (2)
Multiply equation (1) by (3) & (4) by (5) then subtract
$- \frac{9}{y} = 30$
$- \frac{25}{y} = 30$
- (+) -
______________________
$\frac{16}{y} = 0 \Rightarrow [\frac{1}{y} = 0]$
Now from equation (1) $\frac{5}{x} = 10 + \frac{3}{y} = 10$
$[\frac{1}{x} = 2]$
now $\frac{1}{x} + \frac{1}{y} = 2 + 0 = 2$

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Similar questions

If $\frac{3}{x + y} + \frac{2}{x - y} = 2 a n d \frac{9}{x + y} - \frac{4}{x - y} = 1$ then

(a) x= $\frac{1}{2}$ ,y= $\frac{3}{2}$ (b) x= $\frac{5}{2}$ ,y= $\frac{1}{2}$ (c)x= $\frac{3}{2}$ ,y= $\frac{1}{2}$ (d) x= $\frac{1}{2}$ ,y= $\frac{5}{2}$

Q. Solve the following simultaneous equations graphically.
(1) 2x + 3y = 12 ; x – y = 1
(2) x – 3y = 1 ; 3x – 2y + 4 = 0
(3) 5x – 6y + 30 = 0 ; 5x + 4y – 20 = 0
(4) 3x – y – 2 = 0 ; 2x + y = 8
(5) 3x + y = 10 ; x – y = 2

Q. Solve for

x

and

y

\frac{6}{x - 1} - \frac{3}{y - 2} = 1

\frac{5}{x - 1} + \frac{1}{y - 2} = 2

, where

x \neq 1, y \neq 2

Q. Mark (✓) against the correct answer

If \frac{1}{x} : \frac{1}{y} : \frac{1}{z} = 2 : 3 : 5,

then, x : y : z = ?

(a) 2 : 3 : 5
(b) 15 : 10 : 6
(c) 5 : 3 : 2
(d) 6 : 10 : 15

Q. If

\frac{3}{x} - \frac{2}{y} = 5

and

\frac{4}{x} - \frac{5}{y} = 2

, then

\frac{1}{x} - \frac{1}{y} = ?

Where

(x, y \neq 0)

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If 5x−3y=10 and 3x−5y=6, then 1x+1y=...

The correct option is A 25x−3y=10 -------- (1)3x−5y=6 -------- (2)Multiply equation (1) by (3) & (4) by (5) then subtract−9y=30−25y=30- (+) -______________________16y=0⇒[1y=0]Now from equation (1) 5x=10+3y=10[1x=2]now 1x+1y=2+0=2

If $\frac{5}{x} - \frac{3}{y} = 10$ and $\frac{3}{x} - \frac{5}{y} = 6$ , then $\frac{1}{x} + \frac{1}{y} = . . .$