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Question

If 7m+2n7m2n=53 use properties of proportion to find m:n and hence find m2n2m2+n2.

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Solution

Given
7m+2n7m2n=53

By cross multiplying numerator and denominator,

21m+6n=35m10n

or, 14m=16n

mn=1614=87.......(1)

Now,
m2n2m2+n2

=(mn)21(mn)2+1

=827282+72 [Using (1)]

=15113

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