If a2a3a1a4-a2-a3a1-a4-3 a2-a3a1-a4 then a1- a2- a3- a4 in-

The correct option is C HP Given that, a_ 2 a_ 3 a_ 1 a_ 4 = a_ 2 +a_ 3 a_ 1 +a_ 4 =3( a_ 2 a_ 3 a_ 1 a_ 4 nbsp;) nbsp; Now, a_ 2 a ...

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nth Term of A.P

If a2a3a1a4...

Question

If $\frac{a_{2} a_{3}}{a_{1} a_{4}} = \frac{a_{2} + a_{3}}{a_{1} + a_{4}} = 3 (\frac{a_{2} - a_{3}}{a_{1} - a_{4}})$ then $a_{1}$ , $a_{2}$ , $a_{3}$ , $a_{4}$ in:

A P

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G P

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H P

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none of these

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Similar questions

a_{1}

a_{2}

a_{3}

a_{2}

a_{3}

a_{4}

a_{3}

a_{4}

a_{5}

a_{1}

a_{3}

a_{5}

a_{1}, a_{2}, a_{3}, a_{4}, a_{5} > 0

\frac{a_{1}}{a_{2} + a_{3}} + \frac{a_{2}}{a_{3} + a_{4}} + \frac{a_{3}}{a_{4} + a_{5}} + \frac{a_{4}}{a_{5} + a_{1}} + \frac{a_{5}}{a_{1} + a_{2}} \geq \frac{5}{2}

a_{1}, a_{2}, a_{3}, a_{4}

\frac{1}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{1}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{1}{\sqrt{a_{3}} + \sqrt{a_{4}}}

a_{1}, a_{2}, a_{3}, a_{4}

a_{1}, a_{2}, a_{3}, a_{4}, . . {. ., a}_{20}

a_{1} + a_{20} = 45

a_{1} + a_{2} + a_{3} + a_{4}, . . {. . + a}_{20}

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