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Question

If ab=23, then find the value of 4a+3b3b.

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Solution

First we have to substitute values :-
4a+3b/3b = (4×2)+\frac{\large{3×3}}{\large{3×3}}
=>(4×2)+\frac{\large{(3×3)}}{\large{(3×3)}}
=>8+\frac{\large{9}}{\large{9}}
HERE BOTH 9s ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.
=>\frac{\large{9}}{\large{9}}=\frac{\large{1}}{\large{1}}
=>8+\frac{\large{1}}{\large{1}}
=>8+1
=>9

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