If ab - 23- then find the value of 4a-3b3b-

First we have to substitute values : 4a+3b/3b = (4 #215;2)+= gt;(4 #215;2)+= gt;8+HERE BOTH 9s ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.= gt;= ...

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Standard VII

Mathematics

Long Division Method

If ab = 23,...

Question

If $\frac{a}{b} = \frac{2}{3}$ , then find the value of $\frac{4 a + 3 b}{3 b} .$

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Solution

First we have to substitute values :-
4a+3b/3b = (4×2)+ $\frac{\large{3×3}}{\large{3×3}}$
=>(4×2)+ $\frac{\large{(3×3)}}{\large{(3×3)}}$
=>8+ $\frac{\large{9}}{\large{9}}$
HERE BOTH 9s ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.
=> $\frac{\large{9}}{\large{9}}=$ $\frac{\large{1}}{\large{1}}$
=>8+ $\frac{\large{1}}{\large{1}}$
=>8+1
=>9

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If ab=23, then find the value of 4a+3b3b.

First we have to substitute values :-4a+3b/3b = (4×2)+=>(4×2)+=>8+HERE BOTH 9s ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.=>=>8+=>8+1=>9

If $\frac{a}{b} = \frac{2}{3}$ , then find the value of $\frac{4 a + 3 b}{3 b} .$