Question

If $\frac{a}{b}=\frac{7}{3}$ then find the values of the following ratio.
$\frac{5a+3b}{5a-3b}$

Answer 1

Given that,

$\frac{a}{b}=\frac{7}{3}$

$\therefore \frac{5a+3b}{5a-3b}=\frac{a(5\times \frac{a}{b}+3)}{a(5\times \frac{a}{b}-3)}$

$=\frac{5\times \frac{7}{3}+3}{5\times \frac{7}{3}-3}$

$=\frac{35+9}{35-9}$

$=\frac{44}{26}=\frac{22}{13}$(Ans)