If ab-73 then find the values of the following ratios- a3-b3b3

Given that, ab = 73a^3b^3 = 34327 ∴a^3 b^3b^3 = #160; a^3b^3 1 = 34327 1 = 343 2727 = 31627 (Ans) ...

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Continuity in an Interval

If ab=73 th...

Question

If $\frac{a}{b} = \frac{7}{3}$ then find the values of the following ratios.
$\frac{a^{3} - b^{3}}{b^{3}}$

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\frac{a}{b} = \frac{7}{3}

\frac{a^{3} - b^{3}}{b^{3}}

\frac{a}{b} = \frac{5}{3},

\frac{a^{3} - b^{3}}{b^{3}} .

a + b + c = 9

(3 - a)^{3} + (3 - b)^{3} + (3 - c)^{3} - 3 (3 - a) (3 - b) (3 - c)

If the value of $(\frac{a^{3} - b^{3}}{a^{3} + b^{3}})$ when a = 7 and b = 2 is $\frac{335}{p}$ , then p is 321.

If the value of $(\frac{a^{3} - b^{3}}{a^{3} + b^{3}})$ , when $a = 7$ and $b = 2$ is $\frac{335}{p}$ , then $p$ is $321$ .

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