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Question

If ab=cd=ef prove that :
(a2b2+c2d2+e2f2)=(acbd+cedf+aebf)

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Solution

Given:- ab=cd=ef
To proof:- (a2b2+c2d2+e2f2)=(acbd+cedf+aebf)
Proof:-
Taking L.H.S.-
a2b2+c2d2+e2f2
=(ab)2+(cd)2+(ef)2
=(ab)(ab)+(cd)(cd)+(ef)(ef)
=(ab)(cd)+(cd)(ef)+(ef)(ab)
=(acbd+cedf+aebf)
= R.H.S.
Hence proved

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