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Question

If cosA3=cosB4=15,π2<A<0,π2<B<0 then value of 2sinA+4sinB is

A
4
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B
2
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C
4
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D
0
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Solution

The correct option is A 4
cosA=35sinA=45{sinA=1cos2A}
and cosB=45sinB=35

Therefore,2sinA+4sinB

=2(45)+4(35)=205=4

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