If cos-cos- -a- sin-sin- -b- then a 2 - b 2 sin 2 - - a 2 -1

Eliminate α by sin ^ 2 α #160; +cos ^ 2 α #160; =1 and change cos ^ 2 β #160; to sin ^ 2 β #160; ...

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Differentiation of Inverse Trigonometric Functions

If cosαcosβ...

Question

If $\frac{cos α}{cos β} = a$ , $\frac{sin α}{sin β} = b$ , then $(a^{2} - b^{2}) {sin}^{2} β = a^{2} - 1$

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Similar questions

If $s i n α + s i n β = a a n d c o s α + c o s β = b$ , prove that

(i) $s i n (α + β) = \frac{2 a b}{a^{2} + b^{2}}$

(ii) $c o s (α - β) = \frac{a^{2} + b^{2} - 2}{2}$

s i n α + s i n β = a

c o s α + c o s β = b,

s i n (α + β) = \frac{2 a b}{a^{2} + b^{2}}

c o s (α + β) = \frac{b^{2} - a^{2}}{b^{2} + a^{2}}

sin α + sin β = a

cos α + cos β = b

sin α + β = \frac{m a b}{a^{2} + b^{2}}

m

sin α + sin β = a

cos α + cos β = b

tan \frac{α - β}{2} = \pm \sqrt{\frac{x - a^{2} - b^{2}}{a^{2} + b^{2}}}

x

If $s i n α + s i n β = α$ and $c o s α - c o s β = b$ , then $t a n \frac{α - β}{2} =$

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