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Question

If cosθa=sinθb, then asec2θ+bcosec2θ is equal to

A
a
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B
b
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C
ab
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D
a+b
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Solution

The correct option is D a
Given
cosθa=sinθb
ba=tanθ
acos2θ+bsin2θ
=a×1tannθ1+tannθ+b×2tanθ1+tanθ
=a

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