If log a b - c - log b c - a - log c a - b - then

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Logarithms

If log a b ...

Question

If $\frac{log a}{b - c} = \frac{log b}{c - a} = \frac{log c}{a - b},$ then

a^{a} b^{b} c^{c} = 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a^{b + c} b^{c + a} c^{a + b} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a b c = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{b^{2} - b c + c^{2}} . b^{a^{2} - a c + c^{2}} . c^{b^{2} - b a + a^{2}} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

a + b + c = a b c

\frac{a (b^{2} c^{2} - 1)}{b c + 1} + \frac{b (c^{2} a^{2} - 1)}{c a + 1} + \frac{c (a^{2} b^{2} - 1)}{a b + 1} = 2 a b c

△_{1}, △_{2}

(b, c), (c, a), (a, b)

(a c - b^{2}, a b - c^{2}), (b a - c^{2}, b c - a^{2}), (c b - a^{2}, c a - b^{2})

\frac{△_{1}}{△_{2}} = (a + b + c)^{2}

{log}_{b} a + {log}_{c} a + {log}_{a} b + {log}_{a} c + {log}_{b} c + {log}_{c} b = 3

a, b, c

\neq 1

a b c

Δ A B C, \frac{a}{b^{2} - c^{2}} + \frac{c}{b^{2} - a^{2}} = 0

B =

△ A B C

∠ A B C = 90^{o}

B D ⊥ A C

A B =

c

B C =

a

B D =

p

C A =

b

\frac{1}{a^{2}} + \frac{1}{c^{2}} = \frac{1}{p^{2}}

Join BYJU'S Learning Program