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Question

If sinx+cosxcos3x=atan3x+btan2x+ctanx+d then a+b+c+d=

A
0
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B
2
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C
4
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2
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Solution

The correct option is C 4
sinx+cosxcos3x=atan3x+btan2x+ctanx+d

To find; a+b+c+d, Put, x=π4
We get,

=> 12+12122=a+b+c+d

=> 2×22=a+b+c+d

Hence,

=> a+b+c+d=4

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