If tan 2-tan-1-tan- tan 2-0- then the general value of - is

The correct option is A n π; ∈ I tan 2θ+tanθ1 tanθtan2θ=tan(2θ+θ)=tan3θ=0 3θ=nπ θ=nπ3 ...

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Standard XII

Mathematics

Domain and Range of Trigonometric Ratios

If tan 2θ+t...

Question

If $\frac{tan 2 θ + tan θ}{1 - tan θ tan 2 θ} = 0$ , then the general value of $θ$ is

n π; \in I

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\frac{n π}{3}; \in I

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\frac{n π}{4}; \in I

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\frac{n π}{6}; \in I

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Solution

The correct option is A $n π; \in I$
$\frac{tan 2 θ + tan θ}{1 - tan θ tan 2 θ} = tan (2 θ + θ) = tan 3 θ = 0$
$⟹ 3 θ = n π$
$⟹ θ = \frac{n π}{3}$

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If tan2θ+tanθ1−tanθ tan2θ=0, then the general value of θ is

The correct option is A nπ;∈ Itan2θ+tanθ1−tanθtan2θ=tan(2θ+θ)=tan3θ=0⟹3θ=nπ⟹θ=nπ3

If $\frac{tan 2 θ + tan θ}{1 - tan θ tan 2 θ} = 0$ , then the general value of $θ$ is

The correct option is A $n π; \in I$
$\frac{tan 2 θ + tan θ}{1 - tan θ tan 2 θ} = tan (2 θ + θ) = tan 3 θ = 0$
$⟹ 3 θ = n π$
$⟹ θ = \frac{n π}{3}$