If tan- - - - -tan- - - - - - tan -tan - - then either sin- - - - 0 or sin 2- - sin 2- - sin 2- - 0

The correct option is A TrueLet B C=X so, tan (A+X)/tan (A X)=tan C/ tan B →sin (A+X)cos (A X)/ cos (A+X)sin (A X)=sin C cos Bcos C sin B adjust ...

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Tangent, Cotangent, Secant, Cosecant in Terms of Sine and Cosine

If tanα + β...

Question

If $\frac{t a n (α + β - γ)}{t a n (α - β + γ)} = \frac{t a n γ}{t a n β}$ , then either $s i n (β - γ) = 0$ or $s i n 2 α + s i n 2 β + s i n 2 γ = 0$

True

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False

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0 < α < β < γ < π / 2

tan α < \frac{sin α + sin β + sin γ}{cos α + cos β + cos γ} < tan γ

tan α + tan β + tan γ - tan α tan β tan γ = \frac{sin (α + β + γ)}{cos α cos β cos γ}

α + β - γ = π,

{sin}^{2} α + {sin}^{2} β - {sin}^{2} γ = m sin α sin β cos γ

β = \frac{tan α + tan γ}{1 + tan α tan γ},

sin 2 β = \frac{sin 2 α + sin 2 γ}{1 + sin 2 α sin 2 γ}

tan β = \frac{tan α + tan γ}{1 + tan α tan γ}

sin 2 β = \frac{sin 2 α + sin 2 γ}{1 + sin 2 α sin 2 γ} .

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