Question

If $\frac{x}{m}$ is the mass of adsorbate adsorbed per unit mass of adsorbent, $P$ is the pressure of the adsorbate gas, $a$ and $b$ are constants, which of the following represents "Freundlich adsorption isotherm"?

• A. $log\left(\frac{x}{m}\right)=log\left(K\right)+\frac{1}{n}logP$
• B. $\frac{x}{m}=\frac{a}{b}+\frac{1}{aP}$
• C. $\frac{x}{m}=\frac{1+hP}{aP}$
• D. $\frac{1}{\left(x/m\right)}=\frac{a}{b}+\frac{P}{a}$

Answer 1

The correct option is A $log\left(\frac{x}{m}\right)=log\left(K\right)+\frac{1}{n}logP$

Freundlich expressed an empirical equation for representing the isothermal variation of adsorption of a quantity of gas adsorbed by unit mass of solid adsorbent with pressure. i.e. $\frac{x}{m}=K{P}^{1/n}$

Taking the logarithms of a first equation. it gives $log(\left(\frac{x}{m}\right)=log(K)+\frac{1}{n}logP$