Question

If $\frac{x}{y}=\frac{6}{5}$, then $\frac{x^2+y^2}{x^2-y^2}$ is __________.

• A. $\frac{36}{25}$
• B. $\frac{25}{36}$
• C. $\frac{61}{11}$
• D. $\frac{11}{61}$

Answer 1

The correct option is C $\frac{61}{11}$

Given that,

$\frac{x}{y}=\frac{6}{5}$

$\Rightarrow x=\frac{6y}{5}$

To find, $\frac{x^2+y^2}{x^2-y^2}$

Substituting value of $x$ in this, we get

$\therefore \frac{\frac{36y^2}{25}+y^2}{\frac{36y^2}{25}-y^2}=\frac{61y^2}{11y^2}$ $=\frac{61}{11}$