if difference between the exterior and interior angle of a regular polygon is 60 degree . find its side

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Dear student
$L e t t h e e x t e r i o r a n g l e a n d i n t e r i o r a n g l e o f p o l y g o n b e d e n o t e d b y x a n d y r e s p e c t i v e l y . G i v e n : x - y = 60 ° . . (1) W e k n o w t h a t, y = 180 ° - x \Rightarrow x - 60 ° = 180 ° - x \Rightarrow 2 x = 240 ° \Rightarrow x = 120 ° a n d y = 60 ° A l s o, w e k n o w t h a t x = \frac{360 °}{N u m b e r o f s i d e s} \Rightarrow 120 ° = \frac{360 °}{N u m b e r o f s i d e s} \Rightarrow N u m b e r o f s i d e s = 3$
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if difference between the exterior and interior angle of a regular polygon is 60 degree . find its side

Dear student Let the exterior angle and interior angle of polygon be denoted by x and y respectively.Given: x-y=60° ..(1)We know that, y=180°-x⇒x-60°=180°-x⇒2x=240°⇒x=120°and y=60°Also, we know thatx=360°Number of sides⇒120°=360°Number of sides⇒Number of sides=3 Regards