If difference of pressure between inside and outside of the spherical drop is 70N/m2, then what is the radius of spherical drop ?
Given: Surface tension of water is 70×10−3N/m.
A
1mm
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B
2mm
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C
0.2mm
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D
0.1mm
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Solution
The correct option is B2mm Pressure difference between inside and outside of the spherical drop is, ΔP=2Tr ΔP=70N/m2 T=70×10−3N/m r= Radius of drop ⇒r=2TΔP=2×70×10−370=2×10−3m ∴r=2mm