Question

If different words are formed with all the letters of the word 'AGAIN' and are arranged alphabetically among themselves as in a dictionary, the word at the 50th place will be

• A. NAAGI
• B. NAAIG
• C. IAAGN
• D. IAANG

Answer 1

The correct option is B NAAIG

We have the word $AGAIN$

The words start from $AAGIN=4!=24$

The words start from $GAAIN=\frac{4!}{2!}=12$

The words start from $IAAGN=\frac{4!}{2!}=12$

Number of total words$=48$

$\therefore 49th$ word is $NAAGI$ and $50th$ word is $NAAIG.$

Hence, B is the correct option.