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Question

If direction cosines of a vector of magnitude 3 are 23,13,23 and a>0, then vector is ____

A
2i+j+2k
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B
2ij+2k
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C
i2j+2k
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D
i+2j+2k
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Solution

The correct option is A 2ij+2k
Unit vector with direction cosine 23,13,23 is given by
^a=23^i13^j+23^k

Thus vector with magnitude 3 and direction cosine as above is given by
3^a=2^i^j+2^k

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